Hackerrank Day 5: Loops | Hackerrank Solutions in C++

Objective
In this challenge, we're going to use loops to help us do some simple math. Check out the Tutorial tab to learn more.

Task
Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: n x i = result.

Input Format

A single integer, .

Constraints

Output Format

Print  lines of output; each line  (where ) contains the  of  in the form:
n x i = result.

Sample Input

2

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

Here  is the Solution

#include <iostream>


using namespace std;


int main() {
    int N;
    cin >> N;


    for (int i = 1; i < 11; i++) {
        printf("%i x %i = %i\n", N, i, N * i);
    }


    return 0;
}